v 20050313 1
P 200 100 200 0 1 0 1
{
T 200 200 3 6 0 1 0 0 1
pinnumber=1
T 200 200 3 6 0 0 0 0 1
pinseq=1
T 200 100 5 10 0 0 0 0 1
pintype=pas
}
T 300 50 8 10 0 0 0 0 1
net=VIN24:1
T 200 300 8 10 1 1 0 3 1
value=VIN24
L 200 150 150 250 3 5 0 0 -1 -1
L 250 250 200 150 3 5 0 0 -1 -1
L 200 150 200 100 3 0 0 0 -1 -1