v 20050313 1
P 200 300 200 500 1 0 1
{
T 258 361 5 4 0 1 0 0 1
pinnumber=1
T 258 361 5 4 0 0 0 0 1
pinseq=1
T 200 300 5 10 0 0 0 0 1
pintype=pas
}
L 0 300 400 300 3 10 0 0 -1 -1
T 300 50 8 10 0 0 0 0 1
net=PE:1
T 200 100 8 10 1 1 0 5 1
value=PE
L 100 200 300 200 3 10 0 0 -1 -1
L 50 250 350 250 3 10 0 0 -1 -1
L 150 150 250 150 3 10 0 0 -1 -1